In the circuit given, L=1H, R=110 Ohms, and C=0.001 F. The switch is closed at t=0 and the impressed voltage is E(t)=90V for 0≤t<1 second. At t=1 second, the switch is open again and so, E(t)=0 for t≥1 second. The initial charge and current in the circuit are zero. Solve for the current i(t). Use Laplace transform method.