In the circuit shown below, let $V_s = (100\angle 167) V$, and find: (a) $I_1$ (b) $I_2$ (c) $I_3$
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$Z_{RL} = \frac{5 \cdot j5}{5 + j5} = \frac{j25}{5 + j5} = \frac{j5}{1 + j} = \frac{j5(1 - j)}{(1 + j)(1 - j)} = \frac{j5 + 5}{2} = 2.5 + j2.5$ Show more…
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