0 Ω resistor is given by $P = I^2R$, where $P = 22.0 \, J/s$ and $R = 6.0 \, \Omega$. We can solve for the current $I$ through the 6.0 Ω resistor:
$I = \sqrt{\frac{P}{R}} = \sqrt{\frac{22.0 \, J/s}{6.0 \, \Omega}} = \sqrt{3.667 \, A^2} \approx 1.915 \, A$
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