00:01
In this question we are given with the data as a circuit diagram which is made as like this.
00:36
So, this is our circuit diagram in the question given to us.
00:43
Here we have one register whose value is 24 ohms.
00:48
Here we have another register whose value is 60 ohms.
00:52
Here we have the third register with 30 ohm value and here we have a register with 10 ohm value.
01:01
Over this side we have a 12 volt of battery and over here we have a battery of having volt equals to 0 .7 i into x.
01:16
So first of all we need a transformation that is after the source transformation what is our circuit diagram looks like.
01:29
Source transformation.
01:35
So for that our circuit diagram looks like this.
02:10
So all the three registers are connected over here parallelly and the second register is earth.
02:18
Over here again we have the same amount of our variable voltage that is 7 i x 0 .7 i x and this one is our voltage of 12 volt which according to given circuit register is given as 12 upon 24.
02:41
I x is flowing from here to here as i x was previously flowing from here to here.
02:47
So this is a 24 ohm register.
02:51
This is 30 ohm register and this is a 10 ohm register.
02:56
Now we will start with our calculation and it is given as 0 .5 equals to v dash upon 24 plus v dash upon 30 plus v dash minus v double dash upon 60.
03:19
Here voltages are different across this and this.
03:23
Why so? because they are in parallel combination.
03:29
Solving it further 0 .5 equals to 11 upon 120 v1 minus v double dash upon 60...