In the circuit shown in the diagram below, two thick wires...

In the circuit shown in the diagram below, two thick wires connect a 1.7 volt battery to a Nichrome (NiCr) wire. Each thick connecting wire is 14 cm long, and has a radius of 10 mm. The thick wires are made of copper, which has 8.36e+28 mobile electrons per cubic meter, and an electron mobility of 0.00434 (m/s)/(V/m). The Nichrome wire is 6 cm long, and has a radius of 3 mm. Nichrome has 9e+28 mobile electrons per cubic meter, and an electron mobility of 7e-05 (m/s)/(V/m). What is the magnitude of the electric field in the thick copper wire? V/m What is the magnitude of the electric field in the thin Nichrome wire? V/m

Transcript

00:01 Hello, in this question we have a battery of 1 .7 volts connected to three wires, two of them made up of copper and another one made of micro.

00:10 So the copper wires dimensions with characteristics, everything has been mentioned.

00:15 Like the length of the wire is 14 centimeter, radius is 10 m .m.

00:19 Mobile electrons density, that is number of charges per or number of electrons per meter cubed is 8 .3 .6 multiplied with 10 to the part 28.

00:29 Similarly electron mobility is also given to you for copper.

00:33 Similarly, they have also given you then information about the necromb wire.

00:37 So what have they asked you to find out is what would be the electric field that would be generated inside the copper wire and the chrome wire.

00:46 Now, for understanding this or to solve this question, we need to know one fact.

00:50 That is, the electric field that would be generated inside the wire would depend upon the potential difference across the two ends of the wire.

00:57 Let us say is v divided by the length of the wire so let us say the length of the wire was l then the electric field that will be present inside the wire would be v divided by l.

01:08 Now for finding out the potential difference we would require the information about the resistance of the wire and that would be given as l that is the length of the wire divided by n, e, mu, a.

01:24 So what is n here? that is the number of electrons per unit volume.

01:28 E is the charge of the electron, that is 1 .6 multiplied with 10 to the bar minus 19, mu is the electron mobility, a is the cross -sectional area of the wire.

01:38 So now let us find out first what is the resistance of the wire copper as well as the resistance of the wire necrote...

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