00:01
Okay, so let's kind of talk about what we are given.
00:06
So we have the position.
00:10
I'm just going to call the mercedes of the bins because i don't want to write out mercedes every time.
00:14
So bins would be xm, which is 65 .5 meters per second.
00:23
So i'm going to do these in kind of sections.
00:26
So let's start off with section one, which is when the car makes, a pit stop and then covers the distance of xf is 250 meters.
00:55
So what's the acceleration needed to stop the car? we have vf that is zero meters per second.
01:05
Vf squared equals vo squared plus 2a times xf, minus x -o so plugging some stuff in v squared v o squared plus 2 a x -f so a equals this is going to look kind of weird negative over v squared o so 2xf which is negative over x x which is negative over 65 5 .5 squared, all of that times 2 times 250, which gives us negative 11 .65 meters per second squared.
02:02
So the time is vf equals vo plus a t .0 equals vo plus a t.
02:14
So we need to figure out what time is.
02:16
So t equals negative vo over a, which is negative 65 .5 over negative 11 .65, which gives you 5 .62 seconds.
02:33
Moving on to section 2, that is when the car remains in the pit for the 5 seconds...