In the distance correlation test, we can consider different distances. In particular, we can consider ℓp distance,What p should we use?
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Distance correlation is a measure of dependence between two random variables or datasets, which can capture both linear and non-linear relationships. Show more…
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Continuing with Exercise $6.3 .14$, besides estimation there is also a nice geometric interpretation for testing. For the model $(6.3 .26)$, consider the hypotheses $$ H_{0}: \theta=\theta_{0} \text { versus } H_{1}: \theta \neq \theta_{0} $$ where $\theta_{0}$ is specified. Given a norm $\|\cdot\|$ on $R^{n}$, denote by $d(\mathbf{X}, V)$ the distance between $\mathbf{X}$ and the subspace $V$; i.e., $d(\mathbf{X}, V)=\|\mathbf{X}-\widehat{\boldsymbol{\mu}}\|$, where $\hat{\boldsymbol{\mu}}$ is defined in equation $(6.3 .27) .$ If $H_{0}$ is true, then $\hat{\mu}$ should be close to $\mu=\theta_{0} 1$ and, hence, $\left\|\mathbf{X}-\theta_{0} \mathbf{1}\right\|$ should be close to $d(\mathbf{X}, V) .$ Denote the difference by $$ R D=\left\|\mathbf{X}-\theta_{0} \mathbf{1}\right\|-\|\mathbf{X}-\widehat{\boldsymbol{\mu}}\| $$ Small values of $R D$ indicate that the null hypothesis is true, while large values indicate $H_{1}$. So our rejection rule when using $R D$ is Reject $H_{0}$ in favor of $H_{1}$ if $R D>c$. (a) If the error pdf is the Laplace, $(6.1 .6)$, show that expression $(6.3 .31)$ is equivalent to the likelihood ratio test when the norm is given by $(6.3 .28)$. (b) If the error pdf is the $N(0,1)$, show that expression (6.3.31) is equivalent to the likelihood ratio test when the norm is given by the square of the $l_{2}$ norm, $(6.3 .29) .$
Maximum Likelihood Methods
Maximum Likelihood Tests
Suppose data is obtained from 20 pairs of (x, y) and the sample correlation coefficient is 0.81. (a) Test the hypothesis that H0: ρ = 0 against H1: ρ ≠ 0 with α = 0.01. Reject the null hypothesis. (b) Test the hypothesis that H0: ρ = 0.39 against H1: ρ ≠ 0.39 with α = 0.01. Reject the null hypothesis. (c) Construct a 95% two-sided confidence interval for the correlation coefficient. Round your answer to 3 decimal places: 0.659 ≤ ρ ≤ 0.961.
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