00:01
Hello students so the question is given regarding the two block system so this is a two block system now it is given here that mass of the upper block is here 10 kg and mass of lower block is here 41 kg and here we are applying a 4 of 1004 new black and new static is 0 .6 and new kinetic that is equal to 0 .6 so, and this is your graph.
00:39
Now, first of all, we have to assume that both of the blocks will move together.
00:46
So acceleration is coming up to the f over m plus f.
00:51
So this is here 1004 however 50.
00:55
So this is coming out to the 2 .04 meter per second extra.
01:02
Now, friction required to move.
01:04
So this is npt .m multiplied by b.
01:10
So this is your party of multiplied by 2 .0.
01:14
So this is here 83 .6 note.
01:18
Now we'll check that is the restriction available.
01:22
So i press max.
01:24
This is protein 0 .6.
01:27
Multiplied by then, multi -blad back then, 9 .5.
01:32
So, p.
01:36
So this is 58 .8 as we can say that this much friction is not developed...