Question

In the figure below the two blocks are connected by a string of negligible mass passing over a frictionless pulley. m1 = 10.0 kg and m2 = 6.70 kg and the angle of the incline is ? = 37.0°. Assume that the incline is smooth. (Assume the +x direction is down the incline of the plane.) (a) With what acceleration (in m/s²) does the mass m2 move on the incline surface? Indicate the direction with the sign of your answer. m/s² (b) What is the tension in the string in newtons? N (c) For what value of m1 (in kg) will the system be in equilibrium? kg

          In the figure below the two blocks are connected by
a string of negligible mass passing over a
frictionless pulley. m1 = 10.0 kg and m2 = 6.70 kg
and the angle of the incline is ? = 37.0°. Assume
that the incline is smooth. (Assume the +x direction
is down the incline of the plane.)
(a) With what acceleration (in m/s²) does the mass m2
move on the incline surface? Indicate the direction with
the sign of your answer.
m/s²
(b) What is the tension in the string in newtons?
N
(c) For what value of m1 (in kg) will the system be in
equilibrium?
kg

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In the figure below the two blocks are connected by
a string of negligible mass passing over a
frictionless pulley. m1 = 10.0 kg and m2 = 6.70 kg
and the angle of the incline is ? = 37.0°. Assume
that the incline is smooth. (Assume the +x direction
is down the incline of the plane.)
(a) With what acceleration (in m/s²) does the mass m2
move on the incline surface? Indicate the direction with
the sign of your answer.
m/s²
(b) What is the tension in the string in newtons?
N
(c) For what value of m1 (in kg) will the system be in
equilibrium?
kg

Added by Ryan M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ivan Kochetkov

10/10/2022

Step 1

0 kg - 6.70 kg \times \sin(37.09^\circ)}{10.0 kg + 6.70 kg} \times 9.81 m/s^2\] \[a = \frac{10.0 kg - 6.70 kg \times 0.6018}{10.0 kg + 6.70 kg} \times 9.81 m/s^2\] \[a = \frac{10.0 kg - 4.03 kg}{16.7 kg} \times 9.81 m/s^2\] \[a = \frac{5.97 kg}{16.7 kg} \times 9.81 Show more…

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In the figure below the two blocks are connected by a string of negligible mass passing over a frictionless pulley. m1 = 10.0 kg and m2 = 6.70 kg and the angle of the incline is ̘ = 37.0°. Assume that the incline is smooth. (Assume the +x direction is down the incline of the plane.) With what acceleration (in m/s²) does the mass m2 move on the incline surface? Indicate the direction with the sign of your answer. m/s² What is the tension in the string in newtons? N For what value of m1 (in kg) will the system be in equilibrium? kg

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