00:01
Here we are given the value of voltage v is equal to 130 volt.
00:08
Capacetance c1 is equal to 13 .2 microfarad, capacetance c2 is equal to 6 .35 micro -faird and capacitance c3 is equal to 13 .2 micro -faird.
00:25
Here, capacitance c1 and c2 are parallel capacitance.
00:33
Therefore we can say that here equivalent capacitance will be c1 plus c2 that is just the algebraic sum of both the capacitors.
00:43
C1 is 13 .2 plus c2 is 6 .35 and this turns out to be 19 .55 micro ferret.
00:55
Now this equivalent capacitance and the capacitor 3 are cds.
01:06
Therefore the total capacitance c will be equal to the c equivalent into c3 divided by c equivalent plus c3 this is equal to 19 .55 microfarrad into c3 which is 13 .2 microfarad divided by 19 .55 plus 13 .2.
01:29
Upon solving we will get total capacitance to be 7 .88 micro ferret.
01:38
Now moving on to the a part here we know that in series combination c3 and c equivalent will have same charge.
01:57
That is in series connection the charge will be same and we know that the equation for capacitance is is equal to charge q divided by voltage v or we can say that here charge q will be equal to capacitance into voltage.
02:13
So this is equal to here the capacitance, total capacitance micro -farrad into total voltage is 130 volt.
02:21
So this turns out to be a thousand twenty four point four microclupe.
02:26
So this is the total value of charge.
02:30
Now we need to find the charge on c3 capacitor.
02:37
Which is given by q3 will be equal to q itself.
02:43
So this is equal to 1224 .4 microculum.
02:48
Therefore we can say that here.
02:51
Charge q3 is equal to 0 .00102 coulum.
02:56
So this is the value of charge on third capacitor.
03:01
So this will be part a answer.
03:04
Now we are moving on to the next part, b part, here the potential difference across c3 is given by, we know that equation is v3 is equal to charge divided by capacitance.
03:20
So this is equal to charge is 1024 .4 microculem divided by capacitance is 13 .2 microfarad.
03:28
Upon solving we will get a v3 to be 77 .60 watt.
03:35
This is the voltage across the third capacitor.
03:40
Now moving on to the next part, c part.
03:43
Here we need to find out the energy stored in capacitor u3.
03:50
The equation is half into c3 into v3 square.
03:56
Substituting the values, half into c3 is 13 .2 microfarad into v3 is 77 .6 volt.
04:06
Upon solving we will get a charge stored in capacitor 3 to be 0 .0397 jude.
04:16
So this will be the answer of c part.
04:20
Now we are moving on to the next part d part.
04:24
Here we must know that voltage across c1 and c2 are same because the reason is they are parallel.
04:38
Across the parallel connection, the voltage will be always same.
04:42
Hence, the voltage across c1 and c2 will be same...