Question

In the figure $R_1 = 10.2 ext{ k}Omega$, $R_2 = 14.5 ext{ k}Omega$, $C = 0.415 ext{ mu F}$, and the ideal battery has emf $varepsilon = 16.0 ext{ V}$. First, the switch is closed a long time so that the steady state is reached. Then the switch is opened at time $t = 0$. What is the current in resistor 2 at $t = 4.20 ext{ ms}$?

          In the figure $R_1 = 10.2 	ext{ k}Omega$, $R_2 = 14.5 	ext{ k}Omega$, $C = 0.415 	ext{ mu F}$, and the ideal battery has emf $varepsilon = 16.0 	ext{ V}$. First, the switch is closed a long time so that the steady state is reached. Then the switch is opened at time $t = 0$. What is the current in resistor 2 at $t = 4.20 	ext{ ms}$?

In the figure R1 = 10.2 ext kOmega, R2 = 14.5 ext kOmega, C = 0.415 ext mu F, and the ideal battery has emf varepsilon = 16.0 ext V. First, the switch is closed a long time so that the steady state is reached. Then the switch is opened at time t = 0. What is the current in resistor 2 at t = 4.20 ext ms?

Added by James A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

06/17/2023

Step 1

Find the equivalent resistance of the circuit in steady state: - R1 and Rz are in parallel, so their equivalent resistance is: R1||Rz = (R1*Rz)/(R1+Rz) = (10.2k*14.5k2)/(10.2k+14.5k2) = 6.67k - R and the equivalent resistance of R1||Rz are in series, so the total Show more…

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In the figure, R1 = 10.2 kΩ, R2 = 14.5 kΩ, C = 0.415 μF, and the ideal battery has emf = 16.0 V. First, the switch is closed for a long time so that the steady state is reached. Then, the switch is opened at time t = 0. What is the current in resistor 2 at t = 4.20 ms?