In the figure, a wheel of radius r = 0.169 m is mounted on a frictionless axle. A massless cord is wrapped around the wheel and attached to a box of mass m = 2.57 kg that slides on a frictionless incline at an angle ? = 36.6° with the horizontal. The box accelerates down the surface with a constant acceleration of a = 2.38 m/s2. What is the rotational inertia (in kg·m2) of the wheel about its axle?
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First, we need to find the force acting on the box due to gravity. We can use the formula F = mg, where m is the mass of the box and g is the acceleration due to gravity (9.81 m/s2). So, F = 2.57 kg x 9.81 m/s2 = 25.2 N. Show more…
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