Question

4) In the figure, two 6.20 kg blocks are connected by a massless string over a pulley of radius 1.70 cm and rotational inertia 7.40 x 10^-4 kg·m^2. The string does not slip on the pulley; it is not known whether there is friction between the table and the sliding block; the pulley's axis is frictionless. When this system is released from rest, the pulley turns through 1.20 rad in 0.179s and the acceleration of the blocks is constant. Determine the a) the magnitude of the pulley's angular acceleration, b) the magnitude of either block's acceleration, c) string tension T1, and d) string tension T2.

          4) In the figure, two 6.20 kg blocks are connected by a massless string over a pulley of radius 1.70 cm and rotational inertia 7.40 x 10^-4 kg·m^2. The string does not slip on the pulley; it is not known whether there is friction between the table and the sliding block; the pulley's axis is frictionless. When this system is released from rest, the pulley turns through 1.20 rad in 0.179s and the acceleration of the blocks is constant.

Determine the

a) the magnitude of the pulley's angular acceleration,

b) the magnitude of either block's acceleration,

c) string tension T1, and

d) string tension T2.

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4) In the figure, two 6.20 kg blocks are connected by a massless string over a pulley of radius 1.70 cm and rotational inertia 7.40 x 10^-4 kg·m^2. The string does not slip on the pulley; it is not known whether there is friction between the table and the sliding block; the pulley's axis is frictionless. When this system is released from rest, the pulley turns through 1.20 rad in 0.179s and the acceleration of the blocks is constant.

Determine the

a) the magnitude of the pulley's angular acceleration,

b) the magnitude of either block's acceleration,

c) string tension T1, and

d) string tension T2.

Added by Catalina C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ivan Kochetkov

03/22/2023

Step 1

First, we need to find the angular acceleration of the pulley. We know that the pulley turns through 1.20 rad in 0.179s. We can use the equation: θ = ω₀t + 0.5αt² where θ is the angular displacement, ω₀ is the initial angular velocity (0 in this case), α is the Show more…

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In the figure, two 6.20 kg blocks are connected by a massless string over a pulley of radius 1.70 cm and rotational inertia 7.40 * 10^(-4) kg-m^2. The string does not slip on the pulley; it is not known whether there is friction between the table and the sliding block; the pulley's axis is frictionless. When this system is released from rest, the pulley turns through 1.20 rad in 0.179 s and the acceleration of the blocks is constant. Determine: - The magnitude of the pulley's angular acceleration. - The magnitude of either block's acceleration. - String tension T1. - String tension T2.

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