In the game of roulette, a player can place a $8 bet on the number 5 and have a 1/38 probability of winning. If the metal ball lands on 5, the player gets to keep the $8 paid to play the game and the player is awarded an additional $280. Otherwise, the player is awarded nothing and the casino takes the player's $8. What is the expected value of the game to the player? If you played the game 1000 times, how much would you expect to lose? The expected value is $. (Round to the nearest cent as needed.) The player would expect to lose about $. (Round to the nearest cent as needed.)
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The probability of winning is $\frac{1}{38}$, and the probability of losing is $\frac{37}{38}$. Show more…
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