00:01
In the given question we have to solve the parts by using ground state of mercury.
00:06
The electronic configuration of mercury will be according to its atomic number which is 80.
00:16
So the electronic configuration will be 1 s 2, 2 .2, 2p 6, 3s2, 3p6, 3d10, 4s2, and 2.
00:40
4p6 4d10 5 s 2 5p 6 4 f 14 5 d 10 6 s 2 this is the electronic configuration of mulberry so in the first part it is asked that how many electrons occupy atomic orbital with n is equal to 1 so for n is equal to 1, there is a one orbital that is 1s which have two electrons.
01:21
So the answer for the first part is 2 electron.
01:29
The next part of the question is that how many electrons occupy p atomic orbital? so there are 6 electron in the case of 2p and 6 electron in the case of 3p, 6 electrons.
01:47
In the case of 4p and 6 electron in the case of 5p so in total 24 electron in the case of p orbital so the final answer is that there are 24 electron in the case of p atomic orbital now in the third part of the question it is asked that how many electrons occupy pi atomic orbital so each p orbital has three suborbital which is as px, p .z, and for the p6 configuration, two electrons in each suborbital.
02:36
So for the case of 2p, there are 2 electrons in the case of py...