Question

In the instant of Fig. 11-41, two particles move in an $x y$ plane. Particle $P_{1}$ has mass $6.5 \mathrm{~kg}$ and speed $v_{1}=2.2 \mathrm{~m} / \mathrm{s}$, and it is at distance $d_{1}=1.5 \mathrm{~m}$ from point $O$. Particle $P_{2}$ has mass $3.1 \mathrm{~kg}$ and speed $v_{2}=3.6 \mathrm{~m} / \mathrm{s}$, and it is at distance $d_{2}=$ $2.8 \mathrm{~m}$ from point $O$. What are the (a) magnitude and (b) direction of the net angular momentum of the two particles about $O$ ?

          In the instant of Fig. 11-41, two particles move in an $x y$ plane. Particle $P_{1}$ has mass $6.5 \mathrm{~kg}$ and speed $v_{1}=2.2 \mathrm{~m} / \mathrm{s}$, and it is at distance $d_{1}=1.5 \mathrm{~m}$ from point $O$. Particle $P_{2}$ has mass $3.1 \mathrm{~kg}$ and speed $v_{2}=3.6 \mathrm{~m} / \mathrm{s}$, and it is at distance $d_{2}=$ $2.8 \mathrm{~m}$ from point $O$. What are the
(a) magnitude and (b) direction of the  net angular momentum of the two particles about $O$ ?

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Added by Marc P.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Vishal Gupta

06/13/2022

Step 1

Given: Mass of particle $P_1$, $M_1 = 6.5 \text{ kg}$ Speed of particle $P_1$, $v_1 = 2.2 \text{ m/s}$ Distance of particle $P_1$ from point $O$, $d_1 = 1.5 \text{ m}$ The angular momentum $L_1$ of particle $P_1$ about point $O$ is given by: \[ L_1 = M_1 \times Show more…

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In the instant of Fig. 11-41, two particles move in an $x y$ plane. Particle $P_{1}$ has mass $6.5 \mathrm{~kg}$ and speed $v_{1}=2.2 \mathrm{~m} / \mathrm{s}$, and it is at distance $d_{1}=1.5 \mathrm{~m}$ from point $O$. Particle $P_{2}$ has mass $3.1 \mathrm{~kg}$ and speed $v_{2}=3.6 \mathrm{~m} / \mathrm{s}$, and it is at distance $d_{2}=$ $2.8 \mathrm{~m}$ from point $O$. What are the (a) magnitude and (b) direction of the net angular momentum of the two particles about $O$ ?

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