00:01
Hi, in this question in the first step we are given with emitter current.
00:04
So, here we have emitter current is equal to collector current plus base current.
00:10
So, here we have base current is negligible.
00:15
Therefore, we have collector current is equal to emitter current which is 2 .4 milli ampere.
00:22
Now, we have to calculate the dc voltage.
00:24
So, here we have dc volt, vc will be equal to supply voltage minus collector current into resistor.
00:36
So, collector resistor which is equal to 25 minus 2 .4 into 10 power minus 3 into 5 .3 into 10 power 3 which is equal to.
00:46
So, from this vc will be equal to 12 .28 volts.
00:51
Then we have to calculate the power.
00:54
So, dc output power.
00:56
So, pout is given as vc into ic.
01:00
So, which is equal to 12 .28 into 2 .4 milli ampere.
01:06
So, from this we have pout is equal to 29 .47 milli watt.
01:13
Then for the fourth step we have to calculate peak ic current.
01:18
So, peak ic current is nothing but.
01:20
So, peak ac current is nothing but the collector current which is 2 .4 milli ampere...