In the picture below, the circular arcs \stackrel{ rown}{BC} and \stackrel{ rown}{DE} are shown in red. Show that \angle CAB = \frac{1}{2}(\stackrel{ rown}{BC} - \stackrel{ rown}{DE}).
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Let's label the center of the circle as O, point A as the intersection of the arcs BC and DE, and point F as the intersection of the arcs BC and OE. Show more…
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