) In this reaction, we have:
\[ \begin{array}{l} \mathrm{H}_{2} \mathrm{PO}_{4}{ }^{2-}+\mathrm{H}_{2} \mathrm{O} \\ \text { base acid } \\ \end{array} \]
Since H2PO4^2- is acting as a base and H2O is acting as an acid, the base will accept a proton from the acid.
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