In the reaction indicated in the lab book above if 20 g of...

In the reaction indicated in the lab book above, if 2.0 g of salicylic acid and 3.0 g of acetic anhydride were used what is the limiting reagent and what is the theoretical yield of acetyl salicylic acid? (molar masses: C (12.0 g mol-1); H (1.008 g mol-1); O (16.0 g mol-1) a. Acetic anhydride is the limiting reagent; the theoretical yield is 5.3 g b. Salicylic acid is the limiting reagent; the theoretical yield is 1.3 g c. Acetic anhydride is the limiting reagent; the theoretical yield is 2.6 g d. Salicylic acid is the limiting reagent; the theoretical yield is 2.6 g e. Salicylic acid is the limiting reagent; the theoretical yield is 2.0 g f. Acetic anhydride is the limiting reagent; the theoretical yield is 3.6 g

Transcript

00:01 Hi, in this question we have to find the limiting reactant and the theoretical yield of this product here.

00:07 Now, cellic acid react with acetic anhydride via this reaction.

00:12 So now firstly calculating the molar masses of each.

00:17 So now molar mass of c7h603 is equal to, now molar mass is the sum of the all atoms present in a molecule.

00:26 So here, mass of this c7h6 -o3 is 7 multieth, by mass of each carbon atom that is 12 .0 gram per mole plus 6 multiply by mass of each hydrogen that is 1 .008 gram per mole plus 3 multiply by mass of each oxygen is 16 .0 gram per mole so on calculating this we get 138 .05 gram per mole that is molar mass of cellic acid.

01:03 Now, molar mass of acetic anhydride is c4h6 -o3 that is equal to 4 multiply by mass of carbon that is 12 gram per mole plus 6 multiply by 1 .008 gram per mole plus 3 multiply by 16 .0 gram per mole.

01:32 On calculating this, we get molar mass of acetic and hydride as 102 .05 gram per mole.

01:41 Now, molar mass of aspirin, that is, c9, h8, o4, is equal to now 9 multiply by mass of carbon, that is 12 gram per mole, plus 8 ,000.

02:04 By mass of each hydrogen that is 1 .008 gram per mole plus 4 multiply by 16 .0 gram per mole of oxygen now it is equal to 180 .06 gram per mole now firstly we have to calculate the moles of each reactant so now moles of cellic acid that is c7h6 o3 is equal to now that is to mass over molar mass now it is equal to now 2 grams of salicyclic acid is given now molar mass is 138 .05 gram per mole so from here moles is equal to 0 .0145 mole now moles of acetic anhydride that is c4 h6 o3 will be equal to now mass given is 3 .0 gram divided by a molar mass is 102 .05 gram per mole.

03:19 So on calculating, we get 0 .0294 mole...

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