In the winter sport of curling, two teams alternate sliding 20 kg stones on an icy surface in an attempt to end up with the stone closest to the center of a target painted on the ice. During one turn, a player releases a stone that travels 27.9 m before coming to rest. The friction force acting on the stone is 2.0 N. Part A What was the speed of the stone when the player released it?
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First, we need to understand that the stone is slowing down due to the friction force. This means that the stone is undergoing a uniform deceleration. Show more…
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In the winter sport of curling, players give a $20 \mathrm{~kg}$ stone a push across a sheet of ice. A curler accelerates a stone to a speed of $3.0 \mathrm{~m} / \mathrm{s}$ over a time of $2.0 \mathrm{~s}$ a. How much force does the curler exert on the stone? b. What average power does the curler use to bring the stone up to speed?
A 19 kg curling stone travels at 3 m/s [N] down the center line of the ice toward an opponent's stone (19 kg) that is at rest. It strikes the opponent's stone and moves off to the side at 1.8 m/s [N200W]. What is the velocity of the opponent's stone after the collision?
Madhur L.
In the winter sport of curling, players give a $20 \mathrm{kg}$ stone a push across a sheet of ice. The stone moves approximately $40 \mathrm{m}$ before coming to rest. The final position of the stone, in principle, only depends on the initial speed at which it is launched and the force of friction between the ice and the stone, but team members can use brooms to sweep the ice in front of the stone to adjust its speed and trajectory a bit; they must do this without touching the stone. Judicious sweeping can lengthen the travel of the stone by $3 \mathrm{m}$. I A curler pushes a stone to a speed of $3.0 \mathrm{m} / \mathrm{s}$ over a time of $2.0 \mathrm{s}$. Ignoring the force of friction, how much force must the curler apply to the stone to bring it up to speed? A. $3.0 \mathrm{N}$ B. $15 \mathrm{N}$ C. $30 \mathrm{N}$ D. $150 \mathrm{N}$
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