Question

In the xy-plane, a circle with center at point (6, -8) has a radius of 20 units. If the radius of the circle is halved, which of the following points will not be inside the circle? $\rightarrow (-\frac{1}{20}, 0), (\frac{1}{20}, 0), (-\frac{1}{10}, -6), (8, -10)$

Name: in the xy plane a circle with center at point 6 8 has a radius of 20 units if the radius of the circle is halved which of the following points will not be inside the circle rightarrow frac12 92322
Uploaded: 2024-08-09T21:02:23-08:00
Duration: 1 min 8 s
Channel: Jerelyn Nevil
Description: in the xy plane a circle with center at point 6 8 has a radius of 20 units if the radius of the circle is halved which of the following points will not be inside the circle rightarrow frac12 92322

          In the xy-plane, a circle with center at point (6, -8) has a radius of 20 units.
If the radius of the circle is halved, which of the following points will not be inside the circle?
$\rightarrow (-\frac{1}{20}, 0), (\frac{1}{20}, 0), (-\frac{1}{10}, -6), (8, -10)$

$in the xy plane a circle with center at point 6 8 has a radius of 20 units if the radius of the circle is halved which of the following points will not be inside the circle rightarrow frac12 92322$

Added by Jacqueline P.

Geometry A Common Core Curriculum

Ron Larson, Laurie Boswell 1st Edition

Instant Answer

Solved by Expert Jerelyn Nevil

08/09/2024

Step 1

If the radius is halved, the new radius is 10. The equation of the new circle is $(x-6)^2 + (y+8)^2 = 10^2 = 100$. A point (x, y) is inside the circle if $(x-6)^2 + (y+8)^2 < 100$. We want to find the point that is not inside the circle, i.e., $(x-6)^2 + (y+8)^2 Show more…

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In the xy-plane, a circle with center at point (6, -8) has a radius of 20 units. If the radius of the circle is halved, which of the following points will not be inside the circle? $\rightarrow (-\frac{1}{20}, 0), (\frac{1}{20}, 0), (-\frac{1}{10}, -6), (8, -10)$