In this activity you will determine if a simple pendulum oscillates faster on the Earth or on the Moon using modeling and DEs.
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Step 1: The period of a simple pendulum is given by the formula $T = 2\pi\sqrt{\frac{L}{g}}$, where $T$ is the period, $L$ is the length of the pendulum, and $g$ is the acceleration due to gravity. Show more…
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In Concept Simulation 10.2 you can explore the concepts that are important in this problem. Astronauts on a distant planet set up a simple pendulum of length 1.20 m. The pendulum executes simple harmonic motion and makes 100 complete oscillations in 430 s. What is the magnitude of the acceleration due to gravity on this planet?
Sri K.
Madhur L.
Allows you to explore the effect of the acceleration due to gravity on pendulum motion, which is the focus of this problem. Astronauts on a distant planet set up a simple pendulum of length $1.2 \mathrm{~m} .$ The pendulum executes simple harmonic motion and makes 100 complete vibrations in $280 \mathrm{~s}$. What is the magnitude of the acceleration due to gravity on this planet?
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University Physics with Modern Physics
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