00:01
So it looks like you've provided or there is provided data for three titrations.
00:06
The reaction is one -to -one, one mole of hcl, reacts with one mole of sodium hydroxide, to produce one mole of sodium chloride and water.
00:17
So to calculate the volume of titrant, this being the volume of hcl, no, sorry, it looks like hcl was titrated, but the titrant is sodium hydroxide.
00:35
So volume sodium hydroxide is simply going to be equal to the final volume minus the initial volume.
00:44
So for trial one, or i'll just go one, two, three, it'll be 21 .6 minus 0 .00 or 21 .60 milliliters.
01:11
For trial two, it's the final 44 .30 minus the initial, 21 .60, giving us 22 .70 milliliters.
01:31
And then for the last one, we've got 20 .20 minus 0 .00 gives us 20 .20 mil liters.
01:43
And then the molarity of the solution, molarity of sodium hydroxide solution.
01:57
That will be the moles of sodium hydroxide divided by the volume sodium hydroxide.
02:08
The mole's sodium hydroxide will be equal to the moles of hcl in the original 25 mil liters at 0 .1016 molar...