00:01
Hello students, in the first part of the question, the circuit is given in this question, then r2 and r3 are in parallel.
00:09
So, the equivalent of r2 and r3 will be the value is given as 6 ohm into 6 ohm upon 6 plus 6 is equals to 3 and then this equivalent and the r1 are in series.
00:34
Now, the equivalent will be equal to the r prime plus r1.
00:40
So, this is equals to 3 plus 6 is equals to 9 ohm.
00:45
So, the equivalent resistance in this circuit is 9 ohm.
00:52
In the next question, we have to calculate the first of all total current.
00:59
So, total current will be equal to the voltage difference upon equivalent resistance which is 9 is equals to 2 ampere.
01:08
2 ampere is the total current.
01:10
Now, we can say that current in the r1 resistance that is i1 current will be equal to the 2 ampere and in the r2 and r3 will be divided equally divided into both arms because both have the equal resistance.
01:32
So, 1 ampere and 1 ampere.
01:35
In the next question, given as circuit is same but the r1 is equals to 1 ohm and r2 is equals to 5 ohm and r3 is equals to 3 ohm is given.
01:55
Now, the equivalent will be r2 and r3 are in parallel.
01:59
So, 5 into 3 upon 5 plus 3 will be equal to the 1 .9 ohm and r prime and r1 are in parallel.
02:09
So, equivalent r prime plus r1.
02:11
So, 1 .9 plus 1 is equals to 2 .9 ohm.
02:18
Now, the current will be equal to the similarly voltage difference is 18 upon the 2 .9 will be equal to the 6 .2 ampere...