00:01
Hello there.
00:01
I see that you are working with certain calculations to find the mass of the water in the beaker and the density of the water where we lead up to calculate the average density that we've calculated.
00:16
So let's begin for the first part that they brought up saying where the volume of the water in a cylinder, i mean in a graduated cylinder is 26 .7 milliliters and the mass of the empty beach.
00:30
Is 78 .013 grams and the mass of the beaker with water is 104 .735 grams so they want to know what is the mass of the beaker i mean the mass of the water in the beaker so how we do that is that we're going to i just show the answer like we're going to basically subtract the water this mass with the water and beaker minus the mass of the beaker so we can get the total of the water and we end up with 26 .72.
01:17
722 grams so with that we're going to find the density of the water.
01:22
So since we know the milliliter of the water is, let me check again, 26 .77 .7.
01:33
Milliliters with that that's how we're able to set up where it's 20 where we put 20 we put our mass over our mass over the volume so we got 26 .722 divided by 26 .77 and we end up with a total of one grams over millimeters for our density so the next one is the same set up where the mass of the empty beaker is still the same is still the same but the mass of the empty beaker is still the same but the mass of the beaker with the water is now 102 .8 i mean 181 grams so now we're going to find the mass so again same calculations that we mines out the beaker plus water and we minus that by the mass of the beaker where we end up getting 24 .168 grams.
02:42
So now we've got to find the density.
02:48
And for the density and the volume for the water and the graduated cylinder is now 24 .2 milliliters.
03:03
So the density is the same thing.
03:06
We put our mass at the top, the firebite.
03:09
Our volume and doing so we end up getting a density of 0 .99 grams over milliliters so now we got all that we're going to calculate the average for this unknown liquid and record below so to do this calculation we add both of them both for our outcomes that we got and we're going to divide it by two so doing so we end up getting so this is the total when you add them, divided by two, you end up getting 0 .995...