In triangle ABC, suppose a=38 cm, b=10 cm, and c=31 cm. Find the measure of the smallest angle in the triangle to the nearest tenth of a degree.
Added by Linda J.
Step 1
We can do this by comparing the values of a, b, and c. In this case, we see that c is the longest side, so we can use the law of cosines to find the angle opposite to it. The law of cosines states that: c^2 = a^2 + b^2 - 2ab cos(C) where C is the angle opposite Show more…
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