00:01
So, first of all, we will write the given part according to the question.
00:04
So, according to the question, we can see that the value of r is 0 .900 meter.
00:09
Okay? so, first of all, we know that position of a bright fringe, we give the position by ym.
00:25
So, it is always equal to m lambda r upon d.
00:29
Okay? so, the position of next bright fringe, so it is always given by ym plus 1.
00:46
So, that will be equal to m plus 1 lambda r upon d.
00:52
Okay? so, now if we find the del ym, so it will be equal to ym plus 1 minus ym.
00:59
So, if we subtracted these values, then lambda r upon d, this will be common and m plus 1 minus m.
01:06
Okay? so, if we find its value, it will be lambda r upon d...