Indicate the bond polarity (show the partial positive and...

Indicate the bond polarity (show the partial positive and partial negative ends) in the following bonds. (The tail of the arrow indicates the partial positive end of the bond dipole.) a. F - S F ? S F ? S No bond dipole b. F - Se F ? Se F ? Se No bond dipole c. N - S N ? S N ? S No bond dipole d. P - Cl P ? Cl P ? Cl No bond dipole e. As - Br As ? Br As ? Br No bond dipole

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00:01 There, in this question, we are trying to determine bond polarity.

00:07 Well, to determine bond polarity, we use electronegativity.

00:12 And electronegativity show us bond polarity because the greater or the more electronegative element pulls the shared electrons closer to it, making that the negative end of the dipole.

00:55 If the electronegativity values are the same, then there is no bond dipole.

01:09 Okay, so let's go ahead and embark upon looking at the electronegativities for each of these bonds.

01:15 In letter a, we have fluorine bonded to sulfur.

01:21 Well, fluorine has an electronegativity of 4 .0.

01:28 Sulphur has an electronegativity of 2 .5.

01:32 Flooring is more negative.

01:34 So therefore, we would want to select the second option there that shows the arrow pointing to the more negative.

01:40 Usually i see these with a little cross on the plus side.

01:45 So i'm just going to actually be writing those that way.

01:48 All right, but the arrow would be the same.

01:50 The arrow should point at the flooring.

01:52 Letter b, we have flooring, again, with its 4 .0, and it is bonded to selenium.

02:01 Selenium is 2 .4.

02:04 So again, the bond polarity points to the flooring.

02:08 The flooring is the negative end.

02:10 All right, let's look at letter c.

02:15 Letter c, we have two new ones here...

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