00:01
So we have to write the correct round electronic configuration for the following elements.
00:11
And first of them is silicon.
00:15
Silicon has atomic number 14.
00:18
So following the off -bow principle, 1s2, 2 .2, 2p6, 3s2, 3p2, 3p2.
00:32
So this will be the correct ground state electronic configuration because following the off -go principle the next electron will enter in the p sub -shell not in the d sub -shell once the piece of shell is filled it means once thus all the six electrons are being filled in piece of shell then it will enter into the d sub -shell so the ground electronic configuration that is what we have been given 1 s 2 2 s 2 2p 6 3 s 2 3d 2 so is incorrect and it's false as it do not follow of bore principle so this is the a part, now b part.
02:25
We have chromium.
02:29
Chromium has atomic number 24.
02:35
So now the electronic configuration will be argon.
02:41
So this is argon 18 and now we have left with six electrons.
02:49
So this will be 3d 4 .4 s2.
02:58
Now there is a exception and the exception is this is the electronic configuration we have been given here right but since half filled d orbital are more stable that is d5 hence correct electronic or we say ground ground state electronic configuration ground state electronic configuration is argon 3d 5 4 s 2 so this will be the correct electronic configuration hence the given ground state electronic electronic configuration is false.
05:20
Now moving to c part...