Indium has two naturally occurring isotopes: In(113), with an atomic weight of 112.904 amu; and

Name: Indium has two naturally occurring isotopes: In(113), with an atomic weight of 112.904 amu; and In(115), with an atomic weight of 114.904 amu. If the average atomic weight for In is 114.818 amu, calculate the fraction-of-occurrences of the isotope In(113).
Uploaded: 2022-04-20T14:55:56-08:00
Duration: 2 min 49 s
Channel: Shaiju T
Description: Indium has two naturally occurring isotopes: In(113), with an atomic weight of 112.904 amu; and In(115), with an atomic weight of 114.904 amu. If the average atomic weight for In is 114.818 amu, calculate the fraction-of-occurrences of the isotope In(113).

Question

Pritesh Ranjan · Accepted Answer

Step 1:
Let the fraction of occurrences of In(113) be ( x ). Therefore, the fraction of occurren

Question

Indium has two naturally occurring isotopes: In(113), with an atomic weight of 112.904 amu; and In(115), with an atomic weight of 114.904 amu. If the average atomic weight for In is 114.818 amu, calculate the fraction-of-occurrences of the isotope In(113).

Please give Ace some feedback