00:01
All right, so we have some inequalities to solve.
00:03
So in the first one, you're going to combine like terms.
00:08
So that would be negative 3n.
00:11
And then the rule is when you divide by a negative, you have to switch the inequality.
00:17
So when i divide that by negative 3, i get negative 1 is now greater than n, or n is less than negative 1.
00:28
So if you have negative 1 in the middle, and then 0, negative 2, you have an open circle at negative 1, and then follow that arrow going left.
00:43
So there's the graph.
00:46
All right, this one's similar.
00:47
So negative p minus 4p would be negative 5p is greater than negative 10.
00:54
I'm going to divide by negative 5.
00:57
And again, because i'm dividing by a negative, i switch the inequality.
01:01
So it's now p is less than two.
01:04
So you're going to put two in the middle, three over here, one over here.
01:10
Again, it's an open circle because it's not equal to.
01:13
And then follow that arrow pointing left.
01:20
All right, this one, so i would combine the like terms on the end here.
01:28
So a positive two minus three would be a negative one.
01:32
I'm going to add the one to the other side.
01:35
So i get 10 is greater.
01:37
Or equal to negative 2m.
01:40
I'm going to divide by a negative 2.
01:42
So again, that's going to make a sign switch.
01:47
So i get negative 5 is less than or equal to negative m.
01:50
And then i always want to write my variable first.
01:53
So m is greater than or equal to negative 5.
02:01
So there's negative 5, negative 4, negative 6...