00:01
Here in the a part when the switch is at position a then here capacitor c1 will be charged.
00:12
And here the voltage across this capacitor c1 will be the applied voltage itself which is delta v.
00:25
Therefore here we can say that q is equal to c into v and as a second.
00:30
As per the question, we need to calculate the initial charge and initial voltage.
00:35
So here initial charge q node will be equal to c1 into the applied voltage delta v and here the initial voltage will be v is equal to delta v.
00:51
So this is the values of initial charge and initial voltage here.
00:57
Now moving on to the next part b part here.
01:00
Here from the diagram we can see that capacitor c2 and c3 are cgs.
01:07
That is since they are cds we can say that the equivalent capacitance c23 will be equal to c2 into c3 divided by c2 plus c3.
01:17
So this is the value of equivalent capacitance here.
01:22
Now moving on to the next part c part here the circuit is as follows.
01:27
Here we have c2 capacitor, c3 capacitor and here we have c1 capacitor.
01:37
Now here in this case the voltage is applied across c1 capacitor.
01:43
Here we can see that c2 and c3 are ceds.
01:49
Hence the equivalent capacitance c23 will be equal to c2 into c3 divided by c2 plus c3.
01:59
Now the circuit can be redrawn as follows.
02:03
Here this is point b.
02:06
Now instead of c2 and c3, we can write just one capacitor, c23.
02:11
And on the other side we have the c1 capacitor.
02:15
So this is c1 capacitor, this is c23 capacitor and the voltage is applied across the c1 capacitor.
02:23
Now we can see that here c23 and c1 are parallel.
02:30
Since they are parallel capacitors, we can say that here.
02:35
Initially, here c1 get charged to q0 when the switch is at b position...