00:01
To determine the molar mass from the osmotic pressure information, we need to know the mass of the compound, which was provided, and we need to know the moles.
00:10
The moles can be calculated from the osmotic pressure information.
00:14
Rearranging the equation, the molarity of the solute in the solution will be equal to osmotic pressure divided by r and t.
00:23
The osmotic pressure is 2 .5 millimeters of mercury that was provided.
00:28
If we divide it by 760, that'll convert it into atmospheres.
00:34
We then divide the atmospheric pressure, the osmotic pressure, in units of atmospheres, by r.
00:41
0 .08 -106 liter atmospheres per kelvin mole, and the kelvin temperature, 25 degrees celsius, is 298 kelvin, and this gives us 1 .345 times 10 to the negative 4 moles of the solute per liter of solution.
01:00
Because the solution was prepared to a volume of 125 mill liters, we can divide that by a thousand to get liters, and then use this as our conversion factor to go from liters of solution to moles of the solute.
01:14
So there were 1 .681 times 10 to the negative 5 moles of the insulin present.
01:21
The molar mass will then be the mass of insulin used to prepare the solution that had this many moles, divided by that many moles, and we get 5 ,950 grams per mole as the molar mass of insulin...