Question

Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. They randomly survey 381 drivers and find that 295 claim to always buckle up. Construct a 96% confidence interval for the population proportion that claim to always buckle up. Use interval notation, for example, [1,5]

Name: insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car they randomly survey 381 drivers and find that 295 claim to always 99499
Uploaded: 2024-06-22T19:29:22-08:00
Duration: 3 min 18 s
Channel: Adi S
Description: insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car they randomly survey 381 drivers and find that 295 claim to always 99499

          Insurance companies are interested in knowing the population
percent of drivers who always buckle up before riding in a car.
They randomly survey 381 drivers and find that 295 claim to always
buckle up. Construct a 96% confidence interval for the population
proportion that claim to always buckle up. Use interval notation,
for example, [1,5]

Added by Michael E.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Adi S

06/22/2024

Step 1

\[ \hat{p} = \frac{\text{number of drivers who always buckle up}}{\text{total number of drivers surveyed}} = \frac{295}{381} \] Show more…

Show all steps

Thanks for your feedback!

Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. They randomly survey 381 drivers and find that 295 claim to always buckle up. Construct a 96% confidence interval for the population proportion that claim to always buckle up. Use interval notation, for example, [1,5]