Question

int fun1(int a, int b) { a = a * 2; return a + b; } int fun2(int &a, int &b) { a = a - 2; b = b * 3; return b - a; } int main() { int x = 3, y = 12; int z = fun1(x, y); cout << fun2(z, y) << " "; cout << x << " " << y << " " << z; return 0; }

Name: int fun1int a int b a a 2 return ab int fun2int a int b a a 2 b b 3 return b a int main int x 3 y 12 int z fun1x y cout fun2zy cout x y z return 0 what are the values of x y and z after the 04645
Uploaded: 2023-12-16T05:46:36-08:00
Duration: 3 min 9 s
Channel: Akash M
Description: int fun1int a int b a a 2 return ab int fun2int a int b a a 2 b b 3 return b a int main int x 3 y 12 int z fun1x y cout fun2zy cout x y z return 0 what are the values of x y and z after the 04645

          int fun1(int a, int b) {
    a = a * 2;
    return a + b;
}

int fun2(int &a, int &b) {
    a = a - 2;
    b = b * 3;
    return b - a;
}

int main() {
    int x = 3, y = 12;
    int z = fun1(x, y);
    cout << fun2(z, y) << " ";
    cout << x << " " << y << " " << z;
    return 0;
}

Added by Ian R.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Akash M

12/16/2023

Step 1

Then, the function fun1 is called with x and y as arguments. Inside fun1, a is assigned the value of x (which is 3) and b is assigned the value of y (which is 12). Then, a is multiplied by 2, so a becomes 6. The function then returns a + b, which is 6 + 12 = 18. Show more…

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int fun1(int a, int b) { a = a * 2; return a + b; } int fun2(int &a, int &b) { a = a - 2; b = b * 3; return b - a; } int main() { int x = 3, y = 12; int z = fun1(x, y); cout << fun2(z, y) << " "; cout << x << " " << y << " " << z; return 0; }