00:01
Hello, so here we have, we're given that we have the integral going from a to b of some function f of x, dx, is, well, going to be equal to e to the fourth minus e squared.
00:17
Well, this is not much really involved here because the function f of x is just going to be e to the x, since the derivative of e to the x we know is e to the x.
00:27
So the antiderivative, the integral, is also going to be e to the x.
00:32
So if we let f of x here be equal to e to the x, and we're going from the bounds of integration, of just going from two to four, so the integral going from two to four of f of x is going to be e to the x, dx.
00:47
Well, we know the integral of e to the x is e to the x, this is going to be e to the x, but then we evaluate from two to four.
00:54
Let me plug in four, and we get e to the four, and we subtract off while we get we plug in two, well, that's going to be e squared...