Intelligence quotas on two different tests are normally distributed. Test A has a mean of 100 and a standard deviation of 14. Test B has a mean of 100 and a standard deviation of 16. Use z-scores to determine which person has the higher IQ: an individual who scores 121 on Test A or an individual who scores 131 on Test B or both have the same IQ?
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Given: - Mean (μ) = 100 - Standard Deviation (σ) = 14 - Score (x) = 121 Using the formula for z-score: \( z = \frac{x - \mu}{\sigma} \) Substitute the values: \( z = \frac{121 - 100}{14} = \frac{21}{14} = 1.5 \) Show more…
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