00:01
Reaction of sodium methoxide with s2 chlorobutane.
00:15
This reaction is an example for sn2 reaction and this reaction proceeds through inversion.
00:29
So in the question, image is given based on the figure given in s2 chlorobutane as chlorine atom is found to be present or lies below the plane.
00:55
Incoming nucleophile approaches from front side.
01:10
So here we find in the transition state both cl, that is ccl, both the carbon chlorine bond cleaves, co bond formation, it occurs simultaneously.
01:38
We find complete removal of chlorine atom led to the formation of r2 methoxy butane.
01:49
And this is an opposite configuration to the configuration is opposite to s2 chlorobutane to that of starting s to chlorobutane.
02:18
Here inversion has occurred hence r2 metoxy butane has formed.
02:28
Inversion is responsible for this change in the configuration.
02:36
So let us represent that in the form of a diagram.
02:38
So this is the structure of s2 chlorobutin, chlorine, butane, s2, chlorobutane.
02:55
In presence of sodium hydroxide, n -a -o -c -h -3 and acetone, it forms r2 -metoxybutan, o -c -h -3, r2 -mithoxybutan, butane...