Ions having equal charges but masses of M and 2M are accelerated through the same potential difference and then enter a uniform magnetic field perpendicular to their path. If the heavier ions follow a circular arc of radius R, what is the radius of the arc followed by the lighter? 4R 3R sqrt(2) * R R / sqrt(2) R / 2
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Given: - Mass of lighter ion, \(M\) - Mass of heavier ion, \(2M\) - Radius of circular arc followed by heavier ion, \(R\) From the explanation: \[ R_1 = \frac{R}{\sqrt{2}} \] ** Show more…
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