00:01
In the given question there are three types of current, phi c, phi e and phi b.
00:11
So, phi c is thing but the collector current and the collector current defines as the amplified output, amplified output current for bipolar junction transition.
00:48
The next is base current i b, i b is base current.
00:57
So, in base current typically 1 percent, 1 percent of emitter current or collector current for small signal transition, small signal transition and the third is emitter current i e, emitter current.
01:37
So, it is equal to the sum of i b and i c.
01:45
So, in the given numerical the collector current formula will be i c is equal to v load by r.
01:57
So, if you put the value, so we get 10 by 5 equal to 2 ampere and we know that i e equal to 2 .5 ampere...