00:02
Hello, friends welcome.
00:04
We have a question here.
00:05
And in the question we have three parts.
00:07
In the first part, we need to solve the probability of a member has to be by mca between 3 .5 years and 4 years.
00:23
So let's make a table from the given data as for the given information.
00:29
So let's create a table over here.
00:32
So our table will be.
00:34
As for the members monthly months of membership and year of membership so let's fill out our table as for the given information so this is for first we have 47 next value will be 84 next is 16 then we have 60 and after that we have 53 then 89 54, 68, 47 months of membership and then 68 again then after 41 then 80 33 and 66 66 then 38 then 38 46 and next is 41 66 36 66 36 36 66 36 36 36 36 36 36 36 36 36 36 36 36 36 36 36 36 36 36 46 okay then we have 7 this is 41 25 and 21 and 21 and into the next column we have here 3 .92 7 then next is 1 .33 5 .00 4 .42 next is 7 .42 then 4 .42 next is 7 .42 then 4 .50 5 .50 5 .50 5 .50 point 67 next value is 3 .92 then we have 5 .67 next is 3 .42 next is 6 .67 next is 6 .67 next is 2 .75 then we have 5 .50 then 3 .17 then 3 .17 then 3 .83 after that we have a value of 3 .42 or 3 .17 and 3 .2.
02:58
Then the last is 2 .0 p.
03:00
So these are our value for the table and let's calculate now our values for first question.
03:10
The probability of that members, that members, members is with yearly, n c a between 3 to 3 .5 to 4 years this was our first question so so this will be calculated as from the above table we have calculated as 3 out of 20 is the probability so let's solve this this will be equal to 1 .5 0 this is our first answer let's help with the second one so here we have probability probability that members with ymca, ymca, 4 years longer.
04:27
4 years longer.
04:31
So for this, from the table we have made earlier, we have to calculate total number of observations are 11 out of 20 again.
04:42
So this will be equal to 0 .5.
04:45
5...