Question

Isopropyl alcohol has a heat of vaporization of $3.99 imes 10^4 ext{J mol}^{-1}$ and a boiling point of $82.30 degree ext{C}$ at 1.000 atm. Using the Clausius-Clapeyron equation, calculate the vapor pressure of isopropyl alcohol at $35.00 degree ext{C}$. 0.411 atm None of these 0.998 atm 7.94 atm 0.126 atm

          Isopropyl alcohol has a heat of vaporization of $3.99 	imes 10^4 	ext{J mol}^{-1}$ and a boiling point of $82.30 degree 	ext{C}$ at 1.000 atm. Using the Clausius-Clapeyron equation, calculate the vapor pressure of isopropyl alcohol at $35.00 degree 	ext{C}$.
0.411 atm
None of these
0.998 atm
7.94 atm
0.126 atm

Isopropyl alcohol has a heat of vaporization of 3.99 imes 10^4 extJ mol^-1 and a boiling point of 82.30 degree extC at 1.000 atm. Using the Clausius-Clapeyron equation, calculate the vapor pressure of isopropyl alcohol at 35.00 degree extC.
0.411 atm
None of these
0.998 atm
7.94 atm
0.126 atm

Added by Beverly W.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Madhur L

08/17/2023

Step 1

Step 1: Write down the Clapeyron equation: ln(P2/P1) = (ΔHvap/R) * (1/T1 - 1/T2) where P1 is the vapor pressure at temperature T1, P2 is the vapor pressure at temperature T2, ΔHvap is the heat of vaporization, R is the gas constant, and ln is the natural Show more…

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Isopropyl alcohol has a heat of vaporization of 3.99 x 10^4 J mol^-1 and a boiling point of 82.30 °C at 1.000 atm. Using the Clausius-Clapeyron equation, calculate the vapor pressure of isopropyl alcohol at 35.00 °C. 0.411 atm None of these 0.998 atm 7.94 atm 0.126 atm