00:01
Okay, so i see that you need help with this question, and it says, it has been found that candidates from the mba program have undergraduate grade point averages that are normally distributed with a standard deviation of 0 .45.
00:13
There was a random sample of 25 applicants is taken, yielding a sample mean of 2 .9.
00:26
It wants you to find a 95 % confidence interval for the population mean.
00:33
So a 95 % confidence interval is a 1 .96z score.
00:38
So you are going to take 2 .9, you're going to do plus or minus 1 .96 times 0 .45 divided by the square root of 25.
00:51
So 0 .45 divided by 5 is 0 .09.
00:56
So 2 .9 plus or minus 1 .96 times 0 .09.
01:01
1 .96 times 0 .09, and so that's 2 .9 plus or minus 0 .1764.
01:13
And so 2 .9 minus 0 .1764 is 2 .7236 comma, and then if i add them together, i'm going to get 3 .0764.
01:30
Then it says, without doing calculations, state whether a 90 % confidence interval for the population mean would be wider or narrower in part a.
01:41
So it would be narrower because as your, oh, i'm sorry, yeah, as your interval or your confidence interval, as your confidence interval, confidence interval decreases, the width decreases...