00:01
For part 2, we have that x is the number of winning games.
00:13
And you also have that x is binomially distributed with n of 30 and p of 0 .6.
00:28
So for the binomial distributed random variable, we have the probability for each value, it is given by n, which is 30, shows x, p which is 0 .6 to the power of x, and 1 minus p, which is 0 .4 to the power of n which is 30 minus x, where x is from 0, 1 to 30 to 30.
01:09
First, we want to find the probability that x is equal to 71, so we plug x into this equation, then we calculate it, it will be 0 .0 to 3.
01:30
Second, we want to find the property that x is less than or equal to 16.
01:36
That will be the sum from x equal to 0 to x equal to 16, or equal to 16, or of px and you can use calculator to calculate that and it is 0 .255.
01:59
Third question, want to find the probability that x is greater than 10 and that is the sum from x equal 11 to n which is 30 of px which is this one right so that will be 0 .9971.
02:28
Fourth question, x is in between 15 to 23.
02:38
So that is the sum from x equal to 15 and 23 of px.
02:47
That would be 0 .0074.
02:51
And lastly, x between 15 and 23 but exclude those two.
03:02
So it's the sum from x equals 16.
03:04
Equal 16 to 23 of px that will be 0 .6710.
03:17
Part 3, we have y, which is the scores on a national statistic exam, is the exam score, and y is normally distributed, which has the mean of 74, and the sd of 12.
03:44
So we have mu is 74, and the sd is 12...