Question

It is possible to make sodium carbonate (molar mass: 105.99 g/mol) from baking soda (sodium bicarbonate, molar mass: 84.006 g/mol) by the following reaction: 2 NaHCO3(s) ? Na2CO3(s) + CO2(g) + H2O(g) You need 5.94 g of Na2CO3. This reaction typically proceeds in 90.0% yield, and your NaHCO3 is only 75.0% pure. What is the minimum mass, in grams, of NaHCO3 you should start with to ensure you produce enough Na2CO3? Give your answer to two decimal places. Answer: 13.95

          It is possible to make sodium carbonate (molar mass: 105.99 g/mol) from baking soda (sodium bicarbonate, molar mass: 84.006 g/mol) by the following reaction:
2 NaHCO3(s) ? Na2CO3(s) + CO2(g) + H2O(g)
You need 5.94 g of Na2CO3. This reaction typically proceeds in 90.0% yield, and your NaHCO3 is only 75.0% pure. What is the minimum mass, in grams, of NaHCO3 you should start with to ensure you produce enough Na2CO3? Give your answer to two decimal places.
Answer: 13.95

It is possible to make sodium carbonate (molar mass: 105.99 g/mol) from baking soda (sodium bicarbonate, molar mass: 84.006 g/mol) by the following reaction:
2 NaHCO3(s) ? Na2CO3(s) + CO2(g) + H2O(g)
You need 5.94 g of Na2CO3. This reaction typically proceeds in 90.0% yield, and your NaHCO3 is only 75.0% pure. What is the minimum mass, in grams, of NaHCO3 you should start with to ensure you produce enough Na2CO3? Give your answer to two decimal places.
Answer: 13.95

Added by Sydney H.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Susan Hallstrom

06/17/2022

Step 1

99 g/mol - Molar mass of NaHCO3 = 84.006 g/mol - Given mass of Na2CO3 = 5.94 g - Using the mole ratio of 2 NaHCO3 : Na2CO3, calculate the moles of NaHCO3 needed: Moles of NaHCO3 = (5.94 g * 2 mol NaHCO3 / 105.99 g) = 0.112 mol NaHCO3 Show more…

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It is possible to make sodium carbonate (molar mass: 105.99 g/mol) from baking soda (sodium bicarbonate, molar mass: 84.006 g/mol) by the following reaction: 2 NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g). You need 5.94 g of Na2CO3. This reaction typically proceeds in 90.0% yield, and your NaHCO3 is only 75.0% pure. What is the minimum mass, in grams, of NaHCO3 you should start with to ensure you produce enough Na2CO3? Give your answer to two decimal places. Answer: 13.95