It takes about 30 s for a jet plane to go from rest to the takeoff speed of 100 mph (44.7 m/s). What is the average horizontal force that the seat exerts on the back of a 80-kg passenger during takeoff?
Added by Cynthia T.
Step 1
Given that the jet plane takes 30 seconds to reach a speed of 44.7 m/s from rest, we can use the formula for acceleration: acceleration = (final velocity - initial velocity) / time acceleration = (44.7 m/s - 0 m/s) / 30 s acceleration = 1.49 m/s^2 Show more…
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A jet plane takes about 30 s to go from rest to the takeoff speed of 100 mph $(44.7 \mathrm{m} / \mathrm{s}) .$ What is the average horizontal force that the seat exerts on the back of a $60-\mathrm{kg}$ passenger during takeoff? How does this force compare to the weight of the passenger?
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