00:05
We are given the two -step mechanism for the decomposition of ozone in the atmosphere.
00:18
First step is reversible.
00:23
Second step is the intermediate of o.
00:29
We are first asked to find an expression for the rate of decomposition of ozone.
00:43
So the rate of formation of ozone would be d concentration of o3 or d t equal the negative k1 nutrition of o3 plus k1 prime concentration of o2 o minus k2 of o 3 we'll call this equation decision 1 and then we can also create an expression here the rate of formation of o b, d, o over d t is equal the k1, concentration of o3, minus k1 prime, concentration of o2, concentration of o, minus k2, concentration of o, minus k2, concentration of o, concentration of o, applying the steady state approximation as o is an intermediate, the t is equal to zero.
02:45
So substituting this into the above equation, we get k1, 03 minus k1 prime, 02, o minus k2, o, minus k2, o, 3, equals 0, 0, 03, equals 0.
03:12
K1, 03 is equal to k1 prime, 02, o plus k2, o3, 03, if we pull out o, k1, 02, plus k2, 03, if we divide here and isolate for o, we divide, here and isolate for o, we we would get k1 concentration of 03 over k1 prime 02 plus k2, concentration of 03...