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Hello students, we will discuss a question from stoichiometry.
00:04
There is a compound that is called as khp, it is potassium hydrogen thallate and 1 .977 gram of this compound was taken, dissolve into 100 milliliter of the water and it was titrated after this against any o 'h abyss and n .oh was taken as 25 milliliter.
00:25
We need to calculate the concentration of nah if the equivalence point was achieved at 24 .16 milliliter.
00:34
Basically, this question is based upon asset and base titration, where naoh is the base and kh is the acid.
00:44
Let's see the structure of khp.
00:47
Khp is a six -membered ring, and this is thalic acid.
00:54
So at one carbon, we can see the carboxylic acid.
01:00
And to the other carbon, the h has been replaced by potassium.
01:08
So this is salt and any which will react with this.
01:15
And after the reaction, the product we can see is sodium potassium thylate c double bond o, o minus na plus acidic hydrogen will be removed plus h2o.
01:36
So, this is a weak asset and this is a strong base and the ratio is one ratio 1...
