Region enclosed by the curves y=cos(z), y=cos(z-c) and the line x=0 equal to the area of the region enclosed by the curve y=cos(x-c) and the lines x=7, y=0?
Added by Nicole G.
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Step 1
Solve cos x = cos(x - c) => cos x - cos(x - c) = -2 sin(x - c/2) sin(c/2) = 0. Since c ∈ (0, π/2) so sin(c/2) ≠ 0, we get sin(x - c/2) = 0 ⇒ x = c/2 + kπ. The first positive intersection is x = c/2 (with k = 0). At x = 0, cos 0 = 1 > cos(−c) = cos c, so on [0, Show more…
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